Einheiten Konverter
Bereich Beschleunigung Druck Energie Geschwindigkeit Gewicht Länge Leistung Macht Temperatur Volumen Winkel Zeit

kgf*m/(kg*K) zu lbf*ft/(lb*°R)

(Kilogram-Force Meter pro Kilogramm pro Kelvin zu Pound-Force-Fuß pro Pfund pro Grad Rankine)

-10% Copy +10% -10% Copy +10%
=
⇄
kgf*m/(kg*K) zu J/kg*°C | kgf*m/(kg*K) zu J/(kg*K) | kgf*m/(kg*K) zu kJ/kg*K | kgf*m/(kg*K) zu kJ/kg*°C | kgf*m/(kg*K) zu cal(th)/g*°C | kgf*m/(kg*K) zu cal(IT)/g*°C | kgf*m/(kg*K) zu kcal(IT)/kg*°C
👎
👍
Konvertieren
2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 kgf*m/(kg*K)ist äquivalent zu 1.8227 lbf*ft/(lb*°R)
Formel verwendet
1 Joule pro Kilogramm pro K = 0.1019716212978 Kilogram-Force Meter pro Kilogramm pro Kelvin
1 Joule pro Kilogramm pro K = 0.185862535177479 Pound-Force-Fuß pro Pfund pro Grad Rankine
∴ 1 Kilogram-Force Meter pro Kilogramm pro Kelvin = 1.8226888305981 Pound-Force-Fuß pro Pfund pro Grad Rankine

Andere kgf*m/(kg*K) Konvertierungen

English Hindi French Spanish Marathi Portuguese Polish Dutch Italian Russian Gujarati Punjabi Turkish Korean
Prozentrechner Bruchrechner KGV GGT Rechner
© 2016-2024. A softUsvista venture!


Let Others Know
✖
Facebook
Twitter
Reddit
LinkedIn
Email
WhatsApp
Copied!