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kcal(IT)/kg*°C zu Btu(th)/(lb*°R)

(Kilokalorie (IT) pro Kilogramm pro Celsius zu Btu (th) pro Pfund pro Grad Rankine)

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kcal(IT)/kg*°C zu J/kg*°C | kcal(IT)/kg*°C zu J/(kg*K) | kcal(IT)/kg*°C zu kJ/kg*K | kcal(IT)/kg*°C zu kJ/kg*°C | kcal(IT)/kg*°C zu cal(th)/g*°C | kcal(IT)/kg*°C zu cal(IT)/g*°C
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Konvertieren
2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 kcal(IT)/kg*°Cist äquivalent zu 1.0007 Btu(th)/(lb*°R)
Formel verwendet
1 Joule pro Kilogramm pro K = 0.0002388458966275 Kilokalorie (IT) pro Kilogramm pro Celsius
1 Joule pro Kilogramm pro K = 0.000239005796104515 Btu (th) pro Pfund pro Grad Rankine
∴ 1 Kilokalorie (IT) pro Kilogramm pro Celsius = 1.00066946713037 Btu (th) pro Pfund pro Grad Rankine

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