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Btu(th)/(lb*°R) zu kcal(IT)/kg*°C

(Btu (th) pro Pfund pro Grad Rankine zu Kilokalorie (IT) pro Kilogramm pro Celsius)

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Btu(th)/(lb*°R) zu J/kg*°C | Btu(th)/(lb*°R) zu J/(kg*K) | Btu(th)/(lb*°R) zu kJ/kg*K | Btu(th)/(lb*°R) zu kJ/kg*°C | Btu(th)/(lb*°R) zu cal(th)/g*°C | Btu(th)/(lb*°R) zu cal(IT)/g*°C | Btu(th)/(lb*°R) zu kcal(IT)/kg*°C
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Konvertieren
2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 Btu(th)/(lb*°R)ist äquivalent zu 0.9993 kcal(IT)/kg*°C
Formel verwendet
1 Joule pro Kilogramm pro K = 0.000239005796104515 Btu (th) pro Pfund pro Grad Rankine
1 Joule pro Kilogramm pro K = 0.0002388458966275 Kilokalorie (IT) pro Kilogramm pro Celsius
∴ 1 Btu (th) pro Pfund pro Grad Rankine = 0.999330980756026 Kilokalorie (IT) pro Kilogramm pro Celsius

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