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Btu(th)/(lb*°F) zu cal(IT)/g*°C

(Btu (th) pro Pfund pro Grad Fahrenheit zu Kalorien (IT) pro Gramm pro Celsius)

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Btu(th)/(lb*°F) zu J/kg*°C | Btu(th)/(lb*°F) zu J/(kg*K) | Btu(th)/(lb*°F) zu kJ/kg*K | Btu(th)/(lb*°F) zu kJ/kg*°C | Btu(th)/(lb*°F) zu cal(th)/g*°C | Btu(th)/(lb*°F) zu cal(IT)/g*°C | Btu(th)/(lb*°F) zu kcal(IT)/kg*°C
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Konvertieren
2X of 1 ▶ 1/2X of 1 ▶
5X of 1 ▶ 1/5X of 1 ▶
8X of 1 ▶ 1/8X of 1 ▶
1 Btu(th)/(lb*°F)ist äquivalent zu 0.9993 cal(IT)/g*°C
Formel verwendet
1 Joule pro Kilogramm pro K = 0.000239005796104515 Btu (th) pro Pfund pro Grad Fahrenheit
1 Joule pro Kilogramm pro K = 0.0002388458966275 Kalorien (IT) pro Gramm pro Celsius
∴ 1 Btu (th) pro Pfund pro Grad Fahrenheit = 0.999330980756026 Kalorien (IT) pro Gramm pro Celsius

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